Sunday, July 26, 2009

Math Help!?!?

Please help me with all these problems if you help me with these problems I pick you as best answer and you can get 10 points....and No im not trying to cheat ok its just that my tutor hasnt taught me this yet so I dont know what to do...and I cant hold back these lessons any longer in school so I need to get them done like now so here are the problems.





5+c/9 =-31





-23 - c=-19





Find three consecutive


integers with a sum of 267.





The Jaspers collect nickels,


dimes, and quarters in a jar.When they


count the change in the jar, there are twice


as many nickels as there are quarters. If


there is $15.30 in dimes and $74.80 in all,


how many quarters are there?





An insurance salesperson


earns a salary of $1,200 per month plus a


commission of 3% of sales.How much


must the salesperson sell to have a monthly


income of at least $1,500?





$1,050 deposited at an interest rate of


2% for 9 months





$18,500 at 9% compounded


semiannually for 5 year

Math Help!?!?
If you put too many questions at the same time, it is a turn off to a lot of people that would normally be willing to help you.





Here is an answer to one of them





3 cons numbers = 267





n + (n + 1) + (n + 2) = 267


3n + 3 = 267


3n = 264


n = 88, 89 and 90
Reply:1)


2)


3)insurance sales person Answer:


1200+(3S/100)=1500 where S is the sales


3S/100=1500-1200


3S/100=300


S/100=300/3


S/100=100


S=100*100=10000


So the answer is 10000


4)


I=PTR/100


I=1050*9*2/100*12


I=15.75 is the interest,


So the total would be 1050+15.75=1065.75








5)
Reply:1. c=-324





2. c=-4
Reply:5 + c/9 = - 31


c/9 = - 36


c = - 324





Answer: c = - 324





- 23 - c = - 19


c = - 4





Answer: c = - 4





Consecutive integers:


Find 1st integer (x):


x + x + 1 + x + 2 = 267


3x = 264


x = 88





2nd integer:


= 88 + 1 or 89





3rd integer:


= 88 + 2 or 90





Answer: the numbers are 88, 89. 90





Nickels, dimes and quarters:


Find quarters (x):


$0.05(2x) + $0.25x = $74.80 - $15.30


$0.10x + $0.25x = $59.50


$0.35x = $59.50


x = 170





Answer: there are 170 quarters.





Sales person:


Find sales (x):


$1,200 + 0.03x = $1,500


0.03x = $300


x = $10,000





Answer: He must sell $10,000.





Interest of deposit:


= $1,050 * 0.02 * 9/12


= $1,050 * 0.02 * 3/4


= $15.75





Balances after compound interest:


= $18,500(1.09^5)


= $18,500 (1.5386239549)


= $28,464.54


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