Sunday, July 26, 2009

Another math riddle!!help?

Mr. Jenson needed to hire a math tutor for his school. he placed a advertisement in the school news. He wrote tha ad in such a way as to attract the most qualifie applicants:





MATH TUTOR NEEDED


10 hours per week


if interested please call:


ABC-DEF-GHIJ


each digit of the telephne is unique.


A,C,G and H are prime numbers


F, I, and J are squear numbers


B, D, E, F and G are even numbers


C is a factor of J


A + D = E + J





What telepone number should interest applicants call???

Another math riddle!!help?
F, I, and J have to be 1,4, or 9 (perfect squares)


B,D,E,F,G are 0,2,4,6,and 8


A,C,G,H are 2,3,5,and 7





So F must be 4





Now,


C is a factor of J so C is either 2 (if J=4) or 3 (if J=9)


But J cannot be 4 since F is 4. Therefore J is 9 and C is 3.





We can then conclude that I is 1.





Now,


A + D = E + J


So


A + D = E + 9


A: 2,5,7


D: 0,2,6,8


E: 0,2,6,8





If E = 0, then A=7, D=2


If E = 2, then A=5, D=6


If E = 6, then A=7, D=8


E cannot equal 8





So G or H is definitely 2, since A cannot be.





G is even, H is not. Therefore G = 2.





Since G is 2, D and E cannot be 2.


So E = 6, and, as shown above, A = 7, and D = 8.





By process of elimination, B = 0 and H = 5.





The phone number:


603-864-2519





Looks like you'll be going up to New Hampshire to get tutored.


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